If n(A)= 40, n(B)=60 and n(A∪B)=80, then find the value of n(A∩B).
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0
Answer:
20
Step-by-step explanation:
no. of a intersection b =n(A)+n(B)-n(AUB)
=60+40-80
=20
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2
Answer:
achi lagi hai to thanks karo please
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