if n(a)=40,n(b)=60and (aub)=80
Find the value of n(AnB)
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Answer:
formula
n(aub)=n(a)+n(b)-n(anb)
80=40+60-n(anb)
80=100-n(anb)
80-100=-n(anb)
-20=-n(anb)
n(anb)=20 ........ans......
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