Question

*If n(A) = 5, n(A∩B) = 2, n(AUB) = 10 then n(B) = ?* 1️⃣ 7 2️⃣ 13 3️⃣ 17 4️⃣ 3​

Answer 1

Answer

n(AUB)= n(A)+n(B)-n(AnB)

10=5+n(B)-2

10=3+n(B)

10-7=n(B)

3=n(B)

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

If n(A) = 5, n(A∩B) = 2, n(AUB) = 10 then n(B) =

1. 7

2. 13

3. 17

4. 3

EVALUATION

Here it is given that

n(A) = 5, n(A∩B) = 2, n(AUB) = 10

Now we are aware of the formula on set theory that

n(AUB) = n(A) + n(B) - n(A∩B)

⇒ 10 = 5 + n(B) - 2

⇒ n(B) = 10 - 5 + 2

⇒ n(B) = 10 - 3

⇒ n(B) = 7

FINAL ANSWER

Hence the correct option is 1️⃣ 7

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