if n(A) =5,n(B) =3,n(A intersection B) =3then express the relation between A,B
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n(AUB)=n(A)+n(B)-n(A intersection B)
n(AUB)=5+3--3=5
Answered by
1
n(AUB)=n(A)+n(B)-n(AIntersectionB)
n(AUB)=5+3-3=5
n(AUB) =n(A)=5
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