Question

If n(A) = 5. n(B) = 6 and n(AU
B)3. then n((A-B)UB)​

Answer 1

Answer:

We know that [math]n(A \cup B) = n(A) + n(B) - n(A \cap B)[/math] Here we are given with ... More

we have the formula n(A u B)=n(A)+n(B)-n(A ∩ If n(A)=3 and n(B)=6, then how are the minimum and maximum elements in AUB? 9,596 Views. Other Answers. Shivani Reddy, lives in ..

We know that [math]n(A \cup B) = n(A) + n(B) - n(A \cap B)[/math] Here we are given with ...

we have the formula n(A u B)=n(A)+n(B)-n(A ∩ /If-n-A-7-n-A-∪-B-11-and-n-B ... More

Generally for 2 different sets A and B UNION operation(A u b)includes the common element

Given that n(A) =7,n(B)=5 and n(AUB)=11We all know a formula i. e, n(AUB) =n(A) +n(B) ...

/If-n-A-7-n-A-∪-B-11-and-n-B ...

Generally for 2 different sets A and B UNION operation(A u b)includes the common elements ...

Given that n(A) =7,n(B)=5 and n(AUB)=11We all know a formula i. e, n(AUB) =n(A) +n(B) ... More

Answer 2

Answer:

8

Step-by-step explanation:

When we say, "A - B in sets," we are referring to the elements of A that are absent from B. So one way would just be to subtract the number of elements that are in both A and B (the intersection) from the number of elements in set A.

$n(A-B)=n(A)-n(A\cap B)$

The second approach is to recognize that the two sets together form a large whole, and that removing B from the sets combined gives us the coloured region.

$n(A-B)=n(A\cup B)-n(B)$

The statement can also be rewritten using intersection symbols as a third option.

$n(A-B)=n(A\cap B')$

$n(A\cup B)=$ Number of elements included both in set A and set B.

The formula for union of two sets is given by:

$n(A\cup B)=n(A) +n(B)-n(A\cap B)$

Given:

$n(A)=5\\n(B)=6\\n(A\cap B)=3$

Find: $n((A-B)\cup B)$

$n((A-B)\cup B)=n(A\cup B)$

Therefore,

$n(A\cup B)=n(A) +n(B)-n(A\cap B)\\=5+6-3\\=11-3\\=8$

Hence the answer for $n((A-B)\cup B)$ is $8$.

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