If n (A) =5 ,n (B) =7 and n(A^B) =3 find n (A^B)
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n(AUB)= n(A) +n(B) -n(AnB)
Plug in the values
11 = 7 + 5 - n (AnB)
11 = 12 - n(AnB)
11–12 - -n (AnB)
-1 = - n(AnB)
So, n(AnB) = 1
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