If n(A) = 5, n(B) =7 and n(A union B) =10, then find n(A intersection B)
Answers
Answered by
13
Step-by-step explanation:
n(A union B)=n(A)+n(B)-n(A inter B)
10. =
5+7- n(A int B )
10=13
n(AinterB)=10-13
-3
Answered by
21
Answer:
n(A intersection B)=2
Explanation step-by-step :
n(A)+ n(B) - (A union B) = n(A intersection B)
5+7-10=n(A intersection B)
12-10= n(A intersection B)
2= n(A intersection B)
Hope you have got it
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