Math, asked by ayesha183, 10 months ago

If n(A) = 5, n(B) =7 and n(A union B) =10, then find n(A intersection B)​

Answers

Answered by uttampatil5522
13

Step-by-step explanation:

n(A union B)=n(A)+n(B)-n(A inter B)

10. =

5+7- n(A int B )

10=13

n(AinterB)=10-13

-3

Answered by rishabh8670
21

Answer:

n(A intersection B)=2

Explanation step-by-step :

n(A)+ n(B) - (A union B) = n(A intersection B)

5+7-10=n(A intersection B)

12-10= n(A intersection B)

2= n(A intersection B)

Hope you have got it

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