Question

If n(A) = 55 n(B)- 62 n(AUB) 15 then in C(AUB)


in sets

answer fast ​

Answer 1

Step-by-step explanation:

I think you mistyped your question and it's

$A \cap B = 15$

Now

$n(A \cup B) = n(A) + n(B) - \: n(A \cap B) \\ \\ \implies \: n(A \cup B) = 55 + 62 - 15 = 102$

Answer 2

Answer:

Correct Question

• If n(A) = 55 n(B)- 62 n(A∩B) 15 then in C(AUB)

$\underline{ \small \underline{ \purple{\sf \: Solution:-}}}$

$\qquad\longrightarrow \sf \: A \cap B = 15A∩B=15 \\ \\ \qquad \sf \: Now\\ \\ \qquad \sf \longrightarrow n(A \cup B) = n(A) + n(B) - \: n(A \cap B) \\ \\ \qquad \longrightarrow \sf \: n(A \cup B) = 55 + 62 - 15 = 102 \\ \\ \qquad \sf \: Hence, \longrightarrow \therefore \underline{\red{ \bold{(A \cup B) =105}}}$