Question

If n(A)=6 and n(B)=7 then n(AXB)=
24
42
13
-1​

Answer 1

$\Huge{\textbf{\textsf{{\color{navy}{ᴀɴ}}{\purple{SW}}{\pink{ᴇʀ}}{\color{pink}{:}}}}}$

Given, n(A)=6and n(B)=7

Therefore, number of relations on A×B=2

[n(A)×n(B)]

=2(6×7) =2 (42)

Step-by-step explanation:

hope it helps you

Answer 2

ᴀɴSWᴇʀ:

Given, n(A)=6and n(B)=7

Therefore, number of relations on A×B=2

[n(A)×n(B)]

=2(6×7) =2 (42)

Step-by-step explanation:

hope it helps you