Question

If n(A)=8 and n(A intersection B)=2, then n((A intersection B)´ intersection A is equal to

Answer 1

Given

n(A)=8

n(AnB)=2

n(AnB)n(A)

2 intersection 8

Answer 2

If n(A) = 8, n(A∩B) = 2, then n((A∩B)'∩A) = 6

Step-by-step explanation:

Given

$n(A)=8$

$n(A\cap B)=2$

To find out

$n((A\cap B)'\cap A)$

We know that

$(A\cap B)'\cap A=A-A\cap B$

Thus,

$n((A\cap B)\cap A)=n(A)-n(A\cap B)=8-2=6$

Hope this answer is helpful.

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