Question

if n(A-B)=10,n(A intersection B)=5 and n(B-A)=20, then find n(B) and n(A union B)​

Answer 1

Step-by-step explanation:

n(A union B)

= n(A-B) + n(A intersection B) + n(B-A)

= 10+5+20

= 35

n(B)

= n(B-A) + n(A intersection B)

= 20+5

= 25