If n(A – B) = 10, n(B – A) = 23, n(A U B) = 50, then n(A ∩ B) is
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Answer:
n(A ∩ B) = 17
Step-by-step explanation:
We know
n(A - B) + n(A ∩ B)= n(A)
And, n(B - A) + n(A ∩ B)= n(B)
Also
n( A ∪ B) = n(A) + n(B) - n( A ∩ B)
Using (i) and (ii)
n(A ∪ B) = [n(A - B) + n(A ∩ B)] + [n(B - A) + n(A ∩ B)] - n(A ∩ B)
n(A ∪ B) = n(A - B) + n(B - A) + n(A ∩ B)
Substituting values.
50 = 10 + 23 + n(A ∩ B)
50 = 33 + n(A ∩ B)
n(A ∩ B) = 17
Please list out in the comments if there are any errors in this solution :)
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