If n(A-B)= 18, n(A UB)= 70 and n(A n B) = 25 then find n(B).
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Answered by
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Answer:
n( B)=52
Step-by-step explanation:
given n(A-B)=18 , n(AUB) =70 ,n(AnB)=25
n(AUB)=n(A-B)+n(AnB)+n(B-C)
70=18+25+n(B-A)
70=43+n(B-A)
n(B-A) = 70-43
n(B-A) =27
now n( B) = n(AnB) +n(B-A)
n(B) = 25 +27
n(B) =52
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