If n(A-B)=18, n(AUB)=70, and n(A intersection B)=25 then find n(B)
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Answered by
142
Given: n(A - B) =18, n(A∪B) =70, n(A ∩ B) =25
n(A∪B) = n(A - B) + n(A ∩ B) + n(B - A)
70 = 18 + 25 + n(B - A)
70 = 43 + n(B - A)
n(B - A) = 70 - 43
n(B - A) = 27
Now n(B) = n(A ∩ B) + n(B - A)
n(B) = 25 + 27
n(B) = 52
n(A∪B) = n(A - B) + n(A ∩ B) + n(B - A)
70 = 18 + 25 + n(B - A)
70 = 43 + n(B - A)
n(B - A) = 70 - 43
n(B - A) = 27
Now n(B) = n(A ∩ B) + n(B - A)
n(B) = 25 + 27
n(B) = 52
Answered by
36
Given:
n(A - B) =18,
n(A∪B) =70,
n(A ∩ B) =25
n(A∪B) = n(A - B) + n(A ∩ B) + n(B - A) 70 = 18 + 25 + n(B - A)
70 = 43 + n(B - A)
n(B - A) = 70 - 43
n(B - A) = 27
Now n(B) = n(A ∩ B) + n(B - A)
n(B) = 25 + 27
n(B) = 52
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