If n( A×B ) =24 , n[p (B) ] =64, then n(A) is :
a) 2
b ) 3
c) 6
d) 4
CORRECT answer only
Answers
Answer:
d) 4
Step-by-step explanation:
n[p(B)] = 2^x
64 = 2^x , where x=6 ( as 2^6 = 64 )
therefore, n(B) = 6
n( A × B ) = n (A) × n (B)
24 = n (A) × 6
therefore, n (A) = 4.
The value of n(A) = 4
Given :
n(A × B) = 24 , n[P(B)] = 64
To find :
The value of n(A) is
a) 2
b ) 3
c) 6
d) 4
Solution :
Step 1 of 3 :
Calculate number of elements in B
The collection of all subsets of a non empty set B is a set of sets. This set is called the power set B and is denoted by P(B)
Let the number of elements in the set B = n
Then the number of elements in power set of B = n[P(B)] = 2ⁿ
By the given condition
∴ Number of elements in the set B = 6
Step 2 of 3 :
Calculate number of elements in A
Here it is given that ,
n(A × B) = 24
⇒ n(A) × n(B) = 24
⇒ n(A) × 6 = 24
⇒ n(A) = 24/6
⇒ n(A) = 4
∴ Number of elements in A = n(A) = 4
Step 3 of 3 :
Choose the correct option
Checking for option (a)
Since number of elements in A = n(A) = 4
So option (a) is not correct
Checking for option (b)
Since number of elements in A = n(A) = 4
So option (b) is not correct
Checking for option (c)
Since number of elements in A = n(A) = 4
So option (c) is not correct
Checking for option (d)
Since number of elements in A = n(A) = 4
So option (d) is correct
Final answer : Hence the correct option is d) 4
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