Question

If n(A-B)=3, n(B-A)=2,n(A union B)=6 then find n(A imtersection B) and n( A symetric B)

pls help me it's urgent

pls give me step by step answer​

Answer 1

Answer:

n(A∩B)=1

and n(A△B)=5

Step-by-step explanation:

n( A∪B)=n( A-B) +n(B-A)+n( A ∩B)

So 6=3+2+n( A∩B)

So n(A∩B)=6-5=1

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Now n( A symetric B)

ie  n(A△B)=n(A∪B)−n(A∩B)

=6-1

=5