Math, asked by Riya6618, 10 months ago

If n(A-B)=36+X and n(B-A)=4*X and n(A intersection B)=2*X such that n(A)=n(B) then find X

Answers

Answered by AndABHIRAM
1

Answer:

12

Step-by-step explanation:

for U R clarity draw the figure (Venn diagrams)

when n(A)=n(B) then n(A-B)=n(B-A)

36+x=4x

36=3x

x=12

Answered by lakigundamala
0

12

n(A-B)= 36+x

n(B-A)=4x

n(A intersection B)= 2x

n(A) = n(A-B)+n(A intersection B)

= 36+x + 2x

= 36+ 3x

n(B) = n(B-A) + n(A intersection B)

= 4x + 2x

=6x

since, n(A)= n(B)

= 36+3x = 6x

= 36 = 6x-3x

= 36= 3x

= x = 12.

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