Question

If n( A∪ B ) =40, and n(A) =22, n(A∩ ) = 8 , then find the value of n(B) , n(B – A) and n ( A-B)

Answer 1

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$Answer: \\n(AUB) =n(U) - n(AUB)c=40-6=34 \\n(AUB)=n(A)+n(B)-n(AnB)=34 \\22+n(B)-8=34 \\14+n(B)=34 \\n(B)=20$

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