If n(A∪B) = 40, n(A-B)=12 and n(A′∩B)=20, then find n(A∩B).
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Given,
n(AUB)=40, n(A-B)=12, n(A'∩B)=20 =>n(B)=20
n(A∪B)=n(A)+n(B)−n(A∩B)
40=12+20-(A∩B)
n(A∩B)=32
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