Math, asked by Thakshaya7734, 16 hours ago

If n(A∪B) = 40, n(A-B)=12 and n(A′∩B)=20, then find n(A∩B).

Answers

Answered by umitbarman16
0

Given,

n(AUB)=40, n(A-B)=12, n(A'∩B)=20 =>n(B)=20

n(A∪B)=n(A)+n(B)−n(A∩B)

40=12+20-(A∩B)

n(A∩B)=32

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