If n (A ⋂ B) = 5, n (A ⋂ C) = 7 and n (A ⋂ B ⋂ C) = 3, then
the minimum possible value of n (B ⋂ C) is
(a) 0 (b) 1 (c) 3 (d) 2
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(c) 3
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1
Option C
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