if n(A-B)=7,n (B-A)=21and n(A U B)=40 then find n(A internation B)
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n(A-B) = 7
n(B-A) = 21
n(A U B) = 40
We have to find n ( A intersection B )
We know that,
n(A U B) =n(A-B) + n(B-A) + n(A intersection B )
40 = 7 + 21 + n(A intersection B )
40 = 28 + n(A intersection B )
n(A intersection B ) = 40 - 28
n(A intersection B ) = 12
Answer:12
hope it helps u..
prakash9810:
how to find whether it is correct or not
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