Question

If n(A*B)+8 and A={1,3}, then n(B)is

Answer 1

Answer:

$\huge\bigstar\red{ANSWER}$

Cartesian product of two sets is obtained by pairing each element of first set with each element of second set.

Given : n(A)=m and n(B)=n

Now, n(A×B)=n(A)×n(B)=m×n=mn.

Thus when m=8 and n=6, we have n(A×B)=48

Step-by-step explanation:

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Answer 2

Answer:

$\huge\bigstar\pink{QUESTION:}$

➡If n(A*B)+8 and A={1,3}, then n(B)is

$\huge\star\green{ANSWER:-}$

➡Cartesian product of two sets is obtained by pairing each element of first set with each element of second set.

Given : n(A)=m and n(B)=n

Now, n(A×B)=n(A)×n(B)=m×n=mn.

Thus when m=8 and n=6, we have n(A×B)=48

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