Question

 If n(A ∪ B ∪C) = 100, n(A) = 4 x, n(B) = 6 x, n(C) = 5 x, n(A ∩ B) = 20,n(B ∩C) = 15, n(A ∩C) = 25 and n(A ∩ B ∩C) = 10 , then the value of x is________​

Answer 1

Answer:21

Explanation:Since, A,B,C are disjoint sets

∴n(A∪B∪C)=n(A)+n(B)+n(C)

=10+6+5=21