if n(A×B) intersection (A×C)=8 and n(B intersection C)=2, find n(A)
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Answer:
n(A) = 4
Step-by-step explanation:
Given that n( (A × B)∩(A × C) ) = 8
And n(B∩C) = 2
To find n(A) consider,
n( (A × B)∩(A × C) ) = 8
n(A × (B∩C)) = 8
n(A) × n(B∩C) = 8
n(A) × 2 = 8 ( ∵ given that n(B∩C) = 2 )
n(A) = 4
Therefore n(A) = 4
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