Math, asked by vkcpadman, 10 months ago

if n(A×B) intersection (A×C)=8 and n(B intersection C)=2, find n(A)​

Answers

Answered by sprao53413
8

Answer:

Please see the attachment

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Answered by aishwaryahk97sl
0

Answer:

n(A) = 4

Step-by-step explanation:

Given that n( (A × B)∩(A × C) ) = 8

And n(B∩C) = 2

To find n(A) consider,

n( (A × B)∩(A × C) ) = 8

n(A × (B∩C)) = 8

n(A) × n(B∩C) = 8

n(A) × 2 = 8    ( ∵ given that n(B∩C) = 2 )

n(A) = 4

Therefore n(A) = 4

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