if n(A_B)=x,n(B_A)=y and n(A intersection B)=z then find n(AuB)
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Answer:
n(A-B)=x
n(B-A)=y
n(A intersection B) =z
n(AuB)=n(A-B) +n(A intersection B) +n(B-A)
n(AuB) =x+z+y
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