If n (Aᵢ) = i + 1 and A₁ ⊂ A₂ ⊂ A₃ ⊂ ..... ⊂ A₉₉, then 99
n( ⋂ Aᵢ) =
i = 11
(a) 99 (b) 98 (c) 100 (d) 101
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