If n(A) = n(B) = 2 n(A intersection B) , then n(A union B) is a multiple of:
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1
Answer:
n(A)=m and n(B)=n ; then n(A×B)=mn.
What is the value of n(A×B)=mn. if m=6 and n
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5
Answer:
n ( A ∪ B ) is a multiple of 3.
Step-by-step explanation:
Given :- n(A) = n(B) = 2 n( A ∩ B)
To Find :- n ( A ∪ B ) is a multiple of which number.
Solution :-
n( A) = n( B) = 2 n(A∩B )
We know n( A ∪ B ) = n( A ) + n( B ) - n( A ∩ B )
Substituting the above given values, we get
n( A ∪ B ) = 2 n( A ∩ B ) + 2 n( A ∩ B ) - n( A ∩ B )
= 4 n( A∩B ) - n( A∩B)
= 3 n(A ∩ B)
As n ( A ∪ B ) = 3 n(A ∩ B)
∴ n ( A ∪ B ) is a multiple of 3. Since 3 is a prime number so 3 doesn't have any factors.
∴ n ( A ∪ B ) is a multiple of 3 only.
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