If n(a)=p and n(b)=q and a.b=pq then find the total number of relation
Answers
Answer:
Relation: A subset of Cartesian product
A relation R from set A to set B is a subset of the Cartesian product A × B. The subset is derived by describing a relationship between elements of A & B.
E.g.: Lets take set A ={a,b,c} & set B ={Amit, Bittu, Bholi , Don}
A*B = { (a,amit),(a,Bittu), (a,Bholi), (a,Don), (b,amit),(b,Bittu), (b,Bholi), (b,Don), (c,amit),(c,Bittu), (c,Bholi), (c,Don)}
Thus A*B has 12 elements
Now if we put a condition (relation), saying first letter of Element in Set B should be the Set A element.
With this condition we get new set as
Conditional Set C = (a,Amit), (b,Bittu), (b, Bholi)}
Set C is sub set of A*B. Thus we say that a relation R from set A to set B is a subset of the Cartesian product A × B
Second element is called image of first element. E.g. “Amit” is image of “a”.
Domain: The set of all first elements of the ordered pairs in a relation. Eg: a & b not c are domain
Range: The set of all second elements in a relation R . E.g. Amit , Bittu and Bholi are range but “Don” is not part of range.
Codomain: Whole set B . Note that range ⊆ codomain. E.g. : Amit , Bittu Bholi and Don are part of codomain.
relation may be represented by :
Roster form
Set-builder method.
An arrow diagram
Step-by-step explanation:
It is number of possible subsets of A × B.
If n(A ) = p and n(B) = q, then n (A × B) = pq , Thus total number of relations/subset is 2pq . Example: Let’s find number of relation for A = {1, 2} and B = {3,4,5}.
Here p=2 & q=3 , so pq = 2*3 = 6
26 = 64, thus it can have 64 relations. Note that relation R from A to A is also stated as a relation on A.
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