if n(a)=p and n(b)=q then the total number of relations that exist between a and b is 2↑{pq}
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Answer:
\text{The total number of non-empty relations from A to B}=2^{pq}-1
Step-by-step explanation:
n(A)=p, n(B)=q then total number of non-empty relations that can be defined from A to B is:
\text{Given: }
\text{n(A)=p and n(B)=q}
\textbf{Relation:}
\text{A relation from A to B is any non-empty subset of }A\times\,B}
\text{Clearly, the number of elements $A\times\,B$ is pq}
\text{Then, the total number of relations from A to B}
=\text{The total number of subsets $A\times\,B$}
=2^{pq}
\text{Hence, the total number of non-empty relations from A to B}=2^{pq}-1
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