Question

If n (A UB) = 8, n(A) = 6, n(B) = 4
then n (A intra section B

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Answer 1

Answer:

2

Step-by-step explanation:

n(A U B) =n(A) +n(B) - n(A intersection B)

8=6+4-n(A intersection B)

n(A intersection B) =10-8

=2

Answer 2

Answer:

2

Step-by-step explanation:

n(A∪B)=n(A)+n(B)−n(AUB)−−−−−−−(1)

Given n(A)=7

n(B)=9

n(A∪B)=14

Substituting in 1

14=7+9−n(AUB)

⇒n(AUB)=16−14=2

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