Question

if n(AnB)=3 n(AuB)=10 then n[p(A∆B)]

Answer 1

A ∆ B = $A \cap B - A \cup B$

n(A ∆ B) = $n(A \cap B) - n(A \cup B)$

Given:
$n(A \cap B)$ = 10

$n(A \cup B)$ = 3

n(A ∆ B) = $n(A \cap B) - n(A \cup B)$

n(A ∆ B) = 10 - 3 = 7

n[P(A)] = $2^n$

n[P(A∆B)] =

$2^7$=128