if n(AUB) = 10, n(B) = 7, n(A) = 5 Then n (A∩B) =
(A) 2
(B) 3
(C) 4
(D) 5
Answers
Answered by
0
Answer:
(A)2
Step-by-step explanation:
let n(A∩B)=x
n(AUB)=n(A) + n(B) - n(A∩B)
10=5+7-x
x=2
Answered by
21
Given:
- n (AUB) = 10
- n (B) = 7
- n (A) = 5
To find:
- n (A∩B) = ?
Solution:
For solving such type of questions, we use the general formula of 2 events in sets.
n (AUB) = n (A) + n (B) - n (A∩B)
⇒ 10 = 5 + 7 - n (A∩B)
⇒ 10 = 12 - n (A∩B)
⇒ 10 + n (A∩B) = 12
⇒ n (A∩B) = 12 - 10
⇒ n (A∩B) = 2
∴ n (A∩B) = 2
Option (A) is correct.
KNOW MORE:
- De Morgan's law states that (A∩B)' = A' U B'
Similar questions