if n (AUB) = 15 n(A)=10 and n(B) =5 then find n.?

Answers
Answer:
Your answer is 0
Step-by-step explanation:
n ( AUB ) = n( A ) + n ( B ) - n( A Intersection B )
15= 10+5- n ( A intersection B )
15 = 15 - n ( A intersection B )
n ( A intersection B ) = 15 - 15
There fore
n ( A intersection B ) = 0
SOLUTION
GIVEN
n(A ∪ B) = 15 , n(A) = 10 , n(B) = 5
TO DETERMINE
n( A ∩ B)
EVALUATION
Here it is given that
n(A ∪ B) = 15 , n(A) = 10 , n(B) = 5
Now
n(A ∪ B) = n(A) + n(B) - n( A ∩ B)
⇒ 15 = 10 + 5 - n( A ∩ B)
⇒ 15 = 15 - n( A ∩ B)
⇒ n( A ∩ B) = 15 - 15
⇒ n( A ∩ B) = 0
FINAL ANSWER
n(A ∩ B) = 0
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