Math, asked by rafeeq1997, 3 months ago

if n (AUB) = 15 n(A)=10 and n(B) =5 then find n.?

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Answers

Answered by aryanparanjape95
2

Answer:

Your answer is 0

Step-by-step explanation:

n ( AUB ) = n( A ) + n ( B ) - n( A Intersection B )

15= 10+5- n ( A intersection B )

15 = 15 - n ( A intersection B )

n ( A intersection B ) = 15 - 15

There fore

n ( A intersection B ) = 0

Answered by pulakmath007
0

SOLUTION

GIVEN

n(A ∪ B) = 15 , n(A) = 10 , n(B) = 5

TO DETERMINE

n( A ∩ B)

EVALUATION

Here it is given that

n(A ∪ B) = 15 , n(A) = 10 , n(B) = 5

Now

n(A ∪ B) = n(A) + n(B) - n( A ∩ B)

⇒ 15 = 10 + 5 - n( A ∩ B)

⇒ 15 = 15 - n( A ∩ B)

⇒ n( A ∩ B) = 15 - 15

⇒ n( A ∩ B) = 0

FINAL ANSWER

n(A ∩ B) = 0

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