Question

if n(AUB)=15 ,n(A)=10,n(B)=5 then find n(A intersection B)​

Answer 1

Step-by-step explanation:

n(AUB)=15,n(A)=10,n(B)=5,n(A intersection B)=?

n(AUB)=n(A)+n(B)-n(A intersection B)

15=10+5-n(A intersection B)

15=15-n( A intersection B)

:.n (A intersection B)= 15-15

:.n (A intersection B)= 0

Answer 2

SOLUTION

GIVEN

n(A ∪ B) = 15 , n(A) = 10 , n(B) = 5

TO DETERMINE

n( A ∩ B)

EVALUATION

Here it is given that

n(A ∪ B) = 15 , n(A) = 10 , n(B) = 5

Now

n(A ∪ B) = n(A) + n(B) - n( A ∩ B)

⇒ 15 = 10 + 5 - n( A ∩ B)

⇒ 15 = 15 - n( A ∩ B)

⇒ n( A ∩ B) = 15 - 15

⇒ n( A ∩ B) = 0

FINAL ANSWER

n(A ∩ B) = 0

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