If n( AUB) = 29, n( A∩B) = 8 & n(B) = 18 , then find n(A)
A) 11
B) 19
C) 27
D) 15
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Answer:
B) 19
Step-by-step explanation:
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n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
Given n(A)=7
n(B)=9
n(A∪B)=14
Substituting in 1
14=7+9−n(A∩B)
⇒n(A∩B)=16−14=2
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