If n( AUB) = 40 and n( A) =36,n(B)=10,n(A')=27
,n(AnB)=6 then find n(u)
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n ( A') = 27 { except A elements}
n (u) = all elements
we know that n (A')= n( u) - n (A)
27= n ( u) - 36
n(u)= 27+36= 63.
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