if n(AUB)=51,n(A)=20,n(B)=44 then find n(A intersection B)
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Answered by
44
n(AUB)= n (A) + n(B) – n ( A ∩ B )n(A)=20
n(b)=44
n(AUB)=51n(AintersectionB)=20+44-51=13 ans
n(b)=44
n(AUB)=51n(AintersectionB)=20+44-51=13 ans
fabi:
tq tq yaar..
haan,,sahi kaha
there's one more bro
ek aur qstn post kiya hai,,bht sare hai :'(
aap irritate toh nai horahe ho na??
Answered by
33
n(A)=20,n(B)=44,n(AUB)=51,n(A intersection B)=?
w.k.t n(A INT B)= n(A)+n(B)-n(AUB) [ by formula]
= 20+44-51
= 13
w.k.t n(A INT B)= n(A)+n(B)-n(AUB) [ by formula]
= 20+44-51
= 13
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