Question

if n(AUB)=51,n(A)=20,n(B)=44 then find n(A intersection B)

Answer 1

 n(AUB)= n (A) + n(B) – n ( A ∩ B )n(A)=20
n(b)=44
n(AUB)=51n(AintersectionB)=20+44-51=13 ans

Answer 2

n(A)=20,n(B)=44,n(AUB)=51,n(A intersection B)=?

w.k.t n(A INT B)= n(A)+n(B)-n(AUB) [ by formula]
                       = 20+44-51
                       = 13