if n(AUB) = 51, n(A) = 20, n(B) = 44 then find the value of n(A∧B)
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i think n(A∧B) = 13 but not exactly
srihitha1234:
yes u are right
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4
there is a formula for it
n(AUB) = n(A)+n(B)-n(A∧B)
now just substitute
51=20+44-n(A∧B)
n(A∧B)=15
n(AUB) = n(A)+n(B)-n(A∧B)
now just substitute
51=20+44-n(A∧B)
n(A∧B)=15
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