if n(AUBUC)=73,n(A)=2x,n(B)=3x n(C)=5x,n(AnB)=10,n(AnC)=5,n(BnC)=15 & n(AnBnC)=3 then the value of x is what?
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Answer:
x=10
Explanation:
given:
n (AU BU C)=73
n(A)=2 x
n(B)=3 x
n(C)=5 x
n(An B)=10
n(An C)=5
n(B n C)=15
n(A n B n C)=3
n(A U B U C)= n(A)+ n(B)+n(C)-n(An B)-n(An C)-n(B n C)+n(A n B n C)
73=2 x+3 x+5 x-10-5-15+3
73=10 x-27
73+27=10 x
100=10 x
x=100/10
x=10
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