History, asked by johnthomas12, 1 year ago

if n(AUBUC)=73,n(A)=2x,n(B)=3x n(C)=5x,n(AnB)=10,n(AnC)=5,n(BnC)=15 & n(AnBnC)=3 then the value of x is what?​

Answers

Answered by arsheenrehal
1

Answer:

x=10

Explanation:

given:

n (AU BU C)=73

n(A)=2 x

n(B)=3 x

n(C)=5 x

n(An B)=10

n(An C)=5

n(B n C)=15

n(A n B n C)=3

n(A U B U C)=  n(A)+ n(B)+n(C)-n(An B)-n(An C)-n(B n C)+n(A n B n C)

73=2 x+3 x+5 x-10-5-15+3

73=10 x-27

73+27=10 x

100=10 x

x=100/10

x=10

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