Question

if n(AXB) = 20, n(a) = 5 then find n(b)​

Answer 1

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Answer 2

The value is $n(B)=4$

Step-by-step explanation:

Given : $n(A\times B)=20$, n(A)=5.

To find : The value of n(B) ?

Solution :

Th expression is written as,

$n(A\times B)=n(A)\times n(B)$

Substitute, n(A)=5 and $n(A\times B)=20$

$20=5\times n(B)$

$n(B)=\frac{20}{5}$

$n(B)=4$

Therefore, the value is $n(B)=4$

#Learn more

If A = {1,2,3}, B = {a,b}. Find n( AXB)​

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