Question

If n coins are tossed simultaneously, the probability of getting head an odd number of times is​

Answer 1

Answer:

If n coins are tossed,

then

$n(s) = {2}^{n}$

then,

if x is event of getting odd no. of heads

$n(x) = \frac{ {2}^{n} }{2} = {2}^{n - 1}$

So then probability of getting odd no. of heads is

$p(x) = \frac{n(x)}{n(s)}$

$p(x) = \frac{ {2}^{n - 1} }{ {2}^{n} } \\ \\ p(x) = {2}^{n - 1 - n} \\ \\ p(x) = {2}^{ - 1} \\ \\ p(x) = \frac{1}{2}$

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