Question

if N drop of same size have each having the same charge collapse to form a bigger drop how will the following vary with respect to a single drop

Answer 1

Let the charge on each drop be Q
Then,
If they collapse to form a bigger one and there is no loss of matter.
Then,
The total charge on bigger drop will be 2Q
Of the area of the two drops separately be A
Then,
Char density will be 2Q/2A
=Q/A(No change)
Capacitance=((Permittivity)A)/D
Potential diff. =Q/Capasitance