Question

If n eN and n > 4 then show that in > n2​

Answer 1

Answer:

any odd opposite number is in the form of

(4p+1) or (4p+3) some integers P

let

n=4p+3

n²-1=(4p+1)²-1=16p²+8p+1-1=

==>n²-1 is divisible by 8

n²-1=(4p+3)²-1=16p²+8p+9-1=

8(2p²+3p+1)

==>n²-1 is divisible by 8

there fore,n²-1 is divisible by 8if n is an odd opposite integers

Step-by-step explanation:

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