Math, asked by MonikaRc, 14 hours ago

If n > 1 And n²- 1 Is Divisible By 8 What Is The Least Value Of n.

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Answered by Anonymous
3

odd number in the form of (2Q +1) where Q is a natural number ,

so, n² -1 = (2Q + 1)² -1

= 4Q² + 4Q + 1 -1

= 4Q² + 4Q

now , checking :

Q = 1 then,

4Q² + 4Q = 4(1)² + 4(1) = 4 + 4 = 8 , it is divisible by 8.

Q =2 then,

4Q² + 4Q = 4(2)² + 4(2) =16 + 8 = 24, it is also divisible by 8 .

Q =3 then,

4Q² + 4Q = 4(3)² + 4(3) = 36 + 12 = 48 , divisible by 8

It is concluded that 4Q² + 4Q is divisible by 8 for all natural numbers.

Hence, n² -1 is divisible by 8 for all odd value of n .

I hope the above text perfectly helps you.

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Answered by Anonymous
8

Step-by-step explanation:

4Q²+4Q is divisible by 8 for all natural numbers. hence n²-1 divisible by 8 for all odd value of n

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