If n> 2 , show that n^5 - 5n^3 + 4n is divisible by 120
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n^5-5n^3 +4n=(n-2)(n-1)(n)(n+1)(n+2)
For n=3,Sn=120
So it is divisible by 120
By finite mathematical induction we can prove Sn divisible by 120
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