IF n IS A NATURAL NO. , THEN FIND THE REMAINDER WHEN 37^(n+2)+16^(n+1)+30^n
IS DIVIDED BY 7.
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Answer = (37 mod 7)^(n+2) + (16 mod 7)^(n+1) + (30 mod 7)^n
= 2^(n+2) + 2^(n+1) +2^n mod 7
= 7* 2^n mod 7
= 0
= 2^(n+2) + 2^(n+1) +2^n mod 7
= 7* 2^n mod 7
= 0
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