Question

If n is a natural number, then (6n2 + 6n)
is always divisible by :
(A) 6 only
(B) 6 and 12 both
(C) 12 only
(D) by 18 only​

Answer 1

Answer:

(a) 6 only

Step-by-step explanation:

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Answer 2

Answer:

If n is a natural number, then (6n2 + 6n)

is always divisible by :

(A) 6 only

(B) 6 and 12 both

(C) 12 only

(D) by 18 onlyIf n is a natural number, then (6n2 + 6n)

is always divisible by :

(A) 6 only

(B) 6 and 12 both

(C) 12 only

(D) by 18 onlyIf n is a natural number, then (6n2 + 6n)

is always divisible by :

(A) 6 only

(B) 6 and 12 both

(C) 12 onlyIf n is a natural number, then (6n2 + 6n)

is always divisible by :

(A) 6 only

(B) 6 and 12 both

(C) 12 onlyIf n is a natural number, then (6n2 + 6n)

is always divisible by :

(A) 6 only

(B) 6 and 12 both

(C) 12 only

(D) by 18 only

(D) by 18 onlyIf n is a natural number, then (6n2 + 6n)

is always divisible by :

(A) 6 only

(B) 6 and 12 both

(C) 12 onlyIf n is a natural number, then (6n2 + 6n)

is always divisible by :

(A) 6 only

(B) 6 and 12 both

(C) 12 only

(D) by 18 onlyIf n is a natural number, then (6n2 + 6n)

is always divisible by :

(A) 6 only

(B) 6 and 12 both

(C) 12 only

(D) by 18 only

(D) by 18 only

(D) by 18 only