Question

If n is a natural number, then (6n2 6n) is always divisible by: select one:

a. 6 and 12 both

b. 6 only

c. 12 only

d. By 18 only

Answer 1

If n is a natural number, then (6n2 + 6n) is always divisible by: [A]. Explanation: (6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.

Answer 2

HIII....

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ANSWER IS 6 AND 12 ONLY ON THE BASIS OF N(N+1)

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