Question

If n is a natural number, then (6n2 + 6n) is always divisible by:

Answer 1

12

6n^2+6n=6n(n+1)

if n=1,

6n(n+1)=12

if n=2,

6n(n+1)=36=12*3

if n=3,

6n(n+1)=72=12*6