Question

If n is a natural number,then 9²n-4²n is always divisible by​

Answer 1

Answer:

${81}^{n} - {16}^{n} = = > {a}^{n} - {b}^{n} \\ is \: always \: divisible \: by \: (a - b) \\ 81 - 16 = 65 \\ so \: factors \: are \: 5 \: and \: 13$

Answer 2

Answer:

81n -16 n =an. bn

is divisible by (a-b)

18-16= 65

so factors are 5 and 13